98m^2-200=0

Solution for 98m^2-200=0 equation:

98m^2-200=0

a = 98; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·98·(-200)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-280}{2*98}=\frac{-280}{196}
=-1+3/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+280}{2*98}=\frac{280}{196}
=1+3/7
$